(x^2-25x)=0

Solution for (x^2-25x)=0 equation:

(x^2-25x)=0

We get rid of parentheses

x^2-25x=0

a = 1; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·1·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*1}=\frac{50}{2}
=25
$